q^2+55q-8750=0

Solution for q^2+55q-8750=0 equation:

q^2+55q-8750=0

a = 1; b = 55; c = -8750;
Δ = b2-4ac
Δ = 552-4·1·(-8750)
Δ = 38025
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{38025}=195$
$q_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(55)-195}{2*1}=\frac{-250}{2}
=-125
$
$q_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(55)+195}{2*1}=\frac{140}{2}
=70
$